You can use the subtraction operator to "add". Or if you really feel like a challenge, traverse through each pair of bits and do bitwise addition. ^_^
Can i sum 2 int without using + operators in c language?
yes using increment or subtraction operator
use increment operator in loop or do double subtraction
Reply:HINT
#include %26lt;stdio.h%26gt;
#include %26lt;conio.h%26gt;
unsigned int add(unsigned int a, unsigned int b)
{
unsigned int c= 0;
unsigned int r= 0;
unsigned int t= ~0;
for (t= ~0; t; t%26gt;%26gt;= 1)
{r%26lt;%26lt;= 1;
r|= (a^b^c)%26amp;1;
c= ((a|b)%26amp;c|a%26amp;b)%26amp;1;
a%26gt;%26gt;= 1;
b%26gt;%26gt;= 1;}
for (t=~0, c=~t; t; t%26gt;%26gt;= 1)
{c%26lt;%26lt;= 1;
c|= r%26amp;1;
r%26gt;%26gt;= 1;}
return c;}
void main ( void ) //so much greater than int main
{
int t;
t = add (7,3);
printf("%d",t);
getch(); //pause program
system("pause"); //just incase getch don't work
}
Reply:I have a different approach for you. You can create a sum function and store it in you header file nextime you can call this function and you ahve need to sue + operator
e:g
void main()
{
int a,b,c;
int sum(int,int); // Function Prototype
a=10;
b=20;
c=sum(a,b)'
getch();
}
/* Store this part in your header file eg: yourheader.h
and next time you just have to include this header file inprogram and you can call sum() function anywhere
c=sum(a,b); */
int sum(int x, int y) // Function definition
{
int z;
z=x+y;
retrun z;
}
Reply:Chk the link
http://in.answers.yahoo.com/question/ind...
Reply:No
narcissus
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