Program to find if a number is odd or even using bitwise operator in C?

if (Number %26amp; 0x1)


//number is odd


else


//number is even

Program to find if a number is odd or even using bitwise operator in C?
When using C as the numeric 0 means boolean false at the same time you can use





if (num %26amp;%26amp; 1) { /*odd here*/ } else {/*even here */}





Loren Soth
Reply:ok.. both your previous posters got the logic right, but the syntax wrong


for a bitwise and operation use a single %26amp;


%26amp;%26amp; is used for logical anding
Reply:main()


{


int x;


scanf("%d",%26amp;x);


if((x%26amp;1)==1)


printf("The number is odd");


else


printf("The Number is even");


}
Reply:every odd number (in binary) has 1 on the end ie 10001 is odd.


so just do if (mynum %26amp;%26amp; 1 == 1) odd


(mynum %26amp;%26amp; 1 == 0) even





AND 1 will put all flags to zero except last one